B is the image
of at least one a
A. Thus, from the example below
we see that the
mapping is not surjective since õ has no pre-image (inverse) under f.
Surjective function → View it...
f : A
→ B is said to
be a surjective function if every b
B is the image
of at least one a
A. Thus, from the example below
we see that the
mapping is not surjective since õ has no pre-image (inverse) under f.
