8.12.2. Αληθεύει για n = 1. Επαγωγικά, a.bⁿ = a.(b.b^n-1) = (a.b).b^n-1 = (b.a).b^n-1 =

             b.(a .b^n-1) = b.(b^n-1.a) = (b.b^n-1).a = bⁿ.a

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